In a head on collision, a 4,000kg truck going 10 m/s eaststrikes a 1,000kg car g

Question

In a head on collision, a 4,000kg truck going 10 m/s eaststrikes a 1,000kg car going 20 m/s west. a). What is the speed and dirction of thewreckage? b). How much kinetic energy was lost in thecollision? Can you help me out with this from start to finish? Thank you. In a head on collision, a 4,000kg truck going 10 m/s eaststrikes a 1,000kg car going 20 m/s west. a). What is the speed and dirction of thewreckage? b). How much kinetic energy was lost in thecollision? Can you help me out with this from start to finish? Thank you.

Explanation / Answer

M V + m v = (M + m)V2     Cap letters refer totruck   V2 is the final speed - applyconservation of mometum Taking East as positive (momenta are vector quantities) 4000 * 10 - 1000 * 10 = 5000 V2 V2 = 20000 / 5000 = 4 m / s    East 1/2 M V2 + 1/2 m v2 - 1/2 (M + m)V22    the loss of kineticenergy 2000 * 100 + 500 * 400 - 2500 * 42 = 3.6 * 10E5J V2 = 20000 / 5000 = 4 m / s    East 1/2 M V2 + 1/2 m v2 - 1/2 (M + m)V22    the loss of kineticenergy 2000 * 100 + 500 * 400 - 2500 * 42 = 3.6 * 10E5J

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