A thin uniform rod, mass = 0.84kg swings about axis pass thruone end of the rod

Question

A thin uniform rod, mass = 0.84kg swings about axis pass thruone end of the rod perpendicular to the plane of the swing.rodswings with period = 1.1s, angular ampl.= 7.6deg. 1.What's the lengh of the rod? 2. What's the max. kinetic energy of the rod at itsswings? A piston of cross-sec. area a is used in hydrolic pressure toexert a small force of mag f on the eclosed liquid.A pipe connectedleads to a larger piston of cross-sec area A. 1.If 4.36cm are the diameters of the piston,what forcemagnitude on the small piston will balance a 28.2kN force on thelarge piston? A thin uniform rod, mass = 0.84kg swings about axis pass thruone end of the rod perpendicular to the plane of the swing.rodswings with period = 1.1s, angular ampl.= 7.6deg. 1.What's the lengh of the rod? 2. What's the max. kinetic energy of the rod at itsswings? A piston of cross-sec. area a is used in hydrolic pressure toexert a small force of mag f on the eclosed liquid.A pipe connectedleads to a larger piston of cross-sec area A. 1.If 4.36cm are the diameters of the piston,what forcemagnitude on the small piston will balance a 28.2kN force on thelarge piston?

Explanation / Answer

A piston of cross-sec. area a is used in hydrolic pressure toexert a small force of mag f on the eclosed liquid.A pipe connectedleads to a larger piston of cross-sec area A. 1.If 4.36cm are the diameters of the piston,what forcemagnitude on the small piston will balance a 28.2kN force on thelarge piston?

Answer;

From the Pascal's law
         F1/A1 = F2/A2
   The magnitude on the small piston is
             F1 = F2 (A1/A2)

   Here F2 = 28.2 kN
           Area of small piston is A1 = d12/4
           Areaof large piston is A2 = d22/4

Substitute the values for F1.

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