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Question

you can see the pic here (because the thing toupload my pics didnt work): http://session.masteringphysics.com/problemAsset/1014207/7/jfk.Figure.P13.38.jpg What is the gauge pressure of the water atthe point P, where the needle meets the wider chamber of thesyringe?(in Pa) What is the gauge pressure of the water atthe point P, where the needle meets the wider chamber of thesyringe?(in Pa) What is the gauge pressure of the water atthe point P, where the needle meets the wider chamber of thesyringe?(in Pa)

Explanation / Answer

Q = (deltaV)/(deltat) = A1V1 = A2V2 = [pi(r^4)(deltaP)] / [8?L] rearrange the equation to solve for deltaP: deltaP = (A*V*8*?*L) / [(pi)r^4] A = pi*r^2 = pi* .001m^2 = (3.14E-16) V= 10m/s ? = 1.0E-3 (the viscosity of water at 20degrees Celsius L= .04m plug them all in and you should get a deltaP (gauge pressure) of 3200 Pa

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