You want to study the linkage between black and green in fish so you do this cro

ID: 172835 • Letter: Y

Question

You want to study the linkage between black and green in fish so you do this cross:

b= mutant, black body

b+= wild-type, gray body

g= mutant, green eye

g+= wild-type, white eye

Wild type dominant over mutant for both

Wild type female(white eyes) ( b+ b, g+ g) crossed with Black green eyed male (b b, g g)

they have 100 total progeny

Progeny: 36 wild type: (white eyes, grey body type)

15 gray, green eyes

36 black, green eyes

13 black, white eyes

What is the recombination frequency between black and green?

A.15 cM

B.13 cM

C.28 cM

D.51 cM

E.72 cM

Given-:

Wild type female ( white eyes) (b+b, g+g) crossed with black green eyed male (bb, gg)

Total progeny = 100

Grey body white eyes = bb+, gg+= 36

Grey body green eyes = bb+, gg = 15

Black body green eyes = bb, gg = 36

Black body white eyes = bb, gg+ =13

The ratio of b+ to b = 51/49 = 1 approx

The ratio of g+ to g = 49/ 51 = 1 approx

The both are in the ratio of 1:1 but the four phenotypes are not in the ratio of 1:1:1:1 so the loci b and g are linked.

The recombination frequency between black and green is

= 15+13/100 =0.28

=28 cM

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