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A sled of mass 50.0 kg is pulled along flat, snow-coveredground. The static firi

ID: 1728709 • Letter: A

Question

A sled of mass 50.0 kg is pulled along flat, snow-coveredground. The static firiction coefficient is 0.30, and the kineticfriction coefficient is 0.10. a. What does the sled weigh? b. What force will be needed to start the sled moving? c. What force is need to keep the sled moving at a constantvelocity? d. Once moving, what total force must be applied to thesled to accelerate it at 3.0 m/s squared? A sled of mass 50.0 kg is pulled along flat, snow-coveredground. The static firiction coefficient is 0.30, and the kineticfriction coefficient is 0.10. a. What does the sled weigh? b. What force will be needed to start the sled moving? c. What force is need to keep the sled moving at a constantvelocity? d. Once moving, what total force must be applied to thesled to accelerate it at 3.0 m/s squared?

Explanation / Answer

a) W = mg = (50)(9.8) = 490 N b) The force needed will be equal to the force of friction, usingthe static coefficient F = Ff    =Fn               Fn= W    = (490)(0.3) = 147 N c) The force needed will be equal to the force of friction, usingthe kinetic coeeficient F = Ff    =Fn            Fn= W = (490)(0.1) = 49 N d) Fnet = ma F - Ff =ma               useFf from part c (kinetic friction) F - 49 = (50)(3)         F = 199 N    =Fn            Fn= W = (490)(0.1) = 49 N d) Fnet = ma F - Ff =ma               useFf from part c (kinetic friction) F - 49 = (50)(3)         F = 199 N
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