Suppose that subsequent to this heating, 1.20 x 10 4 J of thermal energy is remo

Question

Suppose that subsequent to this heating, 1.20 x 104J of thermal energy is removed from the gas isothermally. Find thefinal volume in terms of the initial volume of the example,V0. (Hint: Follow the same steps as in theexample, but in reverse. Use the values calculated in the solutionportion. Also note that the initial volume in this exercise is 1.25V0. My values from the example are: Wenv= 2.70 x 103 Q = 2.70 X 103 W = -2.70 x 103 Suppose that subsequent to this heating, 1.20 x 104J of thermal energy is removed from the gas isothermally. Find thefinal volume in terms of the initial volume of the example,V0. (Hint: Follow the same steps as in theexample, but in reverse. Use the values calculated in the solutionportion. Also note that the initial volume in this exercise is 1.25V0. My values from the example are: Wenv= 2.70 x 103 Q = 2.70 X 103 W = -2.70 x 103 W = -2.70 x 103

Explanation / Answer

.    Q = Wenv   = 1.20 *104   J .    Initial volume(v1) = 1.25 vo   .    Temperature(T) = 300 K . Work done is : .           Wenv   = n R T ln (vf  /vo ) .    ==> ln(vf  / vi )   =     Wenv   / (n R T) .    ==>   (vf  / vI) = exp[Wenv   / (n R T)] .    ==> vf   =   vi   *   exp[Wenv   / (n R T)] .       =   1.25vo  * exp [  1.20 * 104   J / (5.00 * 8.31 * 300 )] .       =   -----------vo   . Solve the above. . Hope this helps u!

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