Consider the reaction 235 92 U + 1 0 n 148 57 La + 87 35 Br + 1 0 n. Element Ato
ID: 1728924 • Letter: C
Question
Consider the reaction 23592U +10n 14857La +8735Br + 10n. Element Atomic Mass (u) 23592U 235.043923 10n 1.008665 14857La 147.932236 8735Br 86.92071119(b) Using values given above, find the total mass of the initialparticles.
1 u
(c) Using the values given above, find the total mass of theparticles after the reaction takes place.
2 u
(d) Subtract the final particle mass from the initial particlemass.
3 u
(e) Convert the answer to part (d) to MeV, obtaining the kineticenergy of the daughter particles, neglecting the kinetic energy ofthe reactants.
4 Mev
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Element Atomic Mass (u) 23592U 235.043923 10n 1.008665 14857La 147.932236 8735Br 86.92071119
(b) Using values given above, find the total mass of the initialparticles.
1 u
(c) Using the values given above, find the total mass of theparticles after the reaction takes place.
2 u
(d) Subtract the final particle mass from the initial particlemass.
3 u
(e) Convert the answer to part (d) to MeV, obtaining the kineticenergy of the daughter particles, neglecting the kinetic energy ofthe reactants.
4 Mev
Thanks--will rate life saver.
Element Atomic Mass (u) 23592U 235.043923 10n 1.008665 14857La 147.932236 8735Br 86.92071119
Explanation / Answer
1 ) Total mass of the initial particles mass of uranium + mass of neutron = 235.04392 +1.008665 Mi = 236.052585 u 2 ) total mass of the particles after thereaction takes place mass of La + mass of Br + mass of neutron = 147.932236 + 86.92071119 + 1.008665 Mf = 235.86161219 u 3 ) M = Mi - Mf = 236.052585 - 235.86161219 = 0.19097281 u 4) 1 u = 931.49 Mev / c2 M = 0.19097281 u = 0.19097281 * 931.49 Mev /c2 = 19.76 * 10-16 MeV = 19.76 * 10-16 MeVRelated Questions
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