An incident ball A of mass 0.10 kg is sliding at 1.4 m/s onthe horizontal tablet

Question

An incident ball A of mass 0.10 kg is sliding at 1.4 m/s onthe horizontal tabletop of negligible friction. It makes ahead -on collision with a target ball B of a mass 0.50 kg at restat the edge of the table. As a result of the collision, theincident ball rebounds, sliding backwards at 0.70 m/s immediatelyafter the collision. a) Calculate the speed of the 0.50 kg target ball immediatelyafter the collision. b) The tabletop is 1.20 m above a level, horizontalfloor. The target ball is projected horizontally andinitially strikes the floor at a horizintal displacementd from the point of collision. Calculate thehorizontal displacement d. An incident ball A of mass 0.10 kg is sliding at 1.4 m/s onthe horizontal tabletop of negligible friction. It makes ahead -on collision with a target ball B of a mass 0.50 kg at restat the edge of the table. As a result of the collision, theincident ball rebounds, sliding backwards at 0.70 m/s immediatelyafter the collision. a) Calculate the speed of the 0.50 kg target ball immediatelyafter the collision. b) The tabletop is 1.20 m above a level, horizontalfloor. The target ball is projected horizontally andinitially strikes the floor at a horizintal displacementd from the point of collision. Calculate thehorizontal displacement d.

Explanation / Answer

(a) Always remember in collision problems that momentum is alwaysconserved: momentum = (mass)(velocity) initial momentum = 0.10(1.4) = 0.14 kg m/s final momentum = 0.10(0.7) + 0.50v = 0.07 kg m/s + 0.50v equate this two and we'll get: 0.14 = 0.07 + 0.5v v = 0.14 m/s (b) First, compute for the time before the ball reaches the floor: y = voyt - (1/2)gt2 (but voy= 0, since the ball is projected horizontally, it doesn't have aninitial vertical velocity) t = (-2y / g) = [(-2)(-1.2) / 9.8)] =0.494871659s Now, since the ball doesn't have a horizontal velocity, its easy tocompute for the horizontal displacement d d = vt = 0.14(0.494871659) = 0.069282032m ˜0.069m

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