While exploring sunken ocean liner, principal researcher foundabsolute pressure

Question

While exploring sunken ocean liner, principal researcher foundabsolute pressure to be 413 atms. Density of seawater is 1025kg/m3 Calculate guge pressure Calculate depth of sunken ocean liner Calculate magnitude F of force due to water on viewing port atthis depth if surface area of port is 0.0100m2 Suppose ocean liner came to rest at surface of ocean before itstarted to sink. Sinking linear reacher terminal velocity of10.0m/s after falling for 30 s Determine magnitude of average acceleration during this periodof time Assuming acceleration was constant calculate distance d belowsurface at which ocean liner reached teminal velocity Calculate time it took ocean liner to sink from surface tobottom of ocean. While exploring sunken ocean liner, principal researcher foundabsolute pressure to be 413 atms. Density of seawater is 1025kg/m3 Calculate guge pressure Calculate depth of sunken ocean liner Calculate magnitude F of force due to water on viewing port atthis depth if surface area of port is 0.0100m2 Suppose ocean liner came to rest at surface of ocean before itstarted to sink. Sinking linear reacher terminal velocity of10.0m/s after falling for 30 s Determine magnitude of average acceleration during this periodof time Assuming acceleration was constant calculate distance d belowsurface at which ocean liner reached teminal velocity Calculate time it took ocean liner to sink from surface tobottom of ocean. Suppose ocean liner came to rest at surface of ocean before itstarted to sink. Sinking linear reacher terminal velocity of10.0m/s after falling for 30 s Determine magnitude of average acceleration during this periodof time Assuming acceleration was constant calculate distance d belowsurface at which ocean liner reached teminal velocity Calculate time it took ocean liner to sink from surface tobottom of ocean.

Explanation / Answer

Given : Absolute pressure ( P ) = 413 atms Density of seawater ( ) = 1025kg/m3 g = 9.8 m/s2 g = 9.8 m/s2 Atmospheric pressure ( Patm ) = 1.013 *105 Pa Guge pressure = Absolute pressure - Atmosphericpressure                        = P - Patm    As we know that    P = Patm + g h Depth ( h ) = P - Patm / g Solve it    As we know that    P = Patm + g h Depth ( h ) = P - Patm / g Solve it

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