A student is asked to determine the index of refraction of aglass slab. After se

Question

A student is asked to determine the index of refraction of aglass slab. After several trials for measurement of angle ofincidence a in the air versus angle of refraction g in glass she records her data as 1. sin g = .037     sin a =.139 2. sin g =.26       sin a =.36 3 sin g   =.42      sin a = .63 4 sin g    =.57      sin a = .83 y axis has sin a and x axis has sin g   How can you use the graph to determine critical angle forglass-air interface Draw a best-fit line and calculate index of refraction frombest-fit line A student is asked to determine the index of refraction of aglass slab. After several trials for measurement of angle ofincidence a in the air versus angle of refraction g in glass she records her data as 1. sin g = .037     sin a =.139 2. sin g =.26       sin a =.36 3 sin g   =.42      sin a = .63 4 sin g    =.57      sin a = .83 y axis has sin a and x axis has sin g   How can you use the graph to determine critical angle forglass-air interface Draw a best-fit line and calculate index of refraction frombest-fit line

Explanation / Answer

.      n1 sini   = n2 sinr      .    ==> n2 = [  n1sini    ]/ sinr   ; Here n1 = refractive index of air = 1 . (1) For   sin g =.037     sin a = .139 .    ==> n2 = [ 1 * 0.139   ] / 0.037 =   3.76 . (2) For   sin g = .26 sin a = .36 .       ==> n2 = [ 1 * 0.36 ]/ 0.26 = 1.38    . Similarly calculate all. . Hope this helps u!

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