Name: niform Problem S: A circular current loop o e paper and perpendicular to t
ID: 1731829 • Letter: N
Question
Name: niform Problem S: A circular current loop o e paper and perpendicular to the in 3.2 s and the ally U n of an initi plane of the loop. The field is us 22 cm is located in a region of a , with the field pointing into the paper teld is ramped down at a continuous rate rate. enif in the loop during the ramp-up process Of 8 ?. ram e the rate. The loop has a resistance o (10 Po up again to 0.42 Tat double (10 points) uced emf in the loop during the ram (10 points) the directions of the current during the ramp-d and the ramp-up processExplanation / Answer
given
circular current loop of radius r = 22 cm
Bi = 0.84 T
Bf = 0 T
dB/dt = -k
dB = -k*dt
(Bf - Bi) = -k(3.2)
k = 0.2625
hence
dB/dt = -0.2625 T/s
after reaching zero
dB/dt = 0.525 T/s
Bf = 0.42 T
R = 8 ohms
a. during ramp down process
EMF = -d(phi)/dt = 0.2625*pi*r^2 = 0.039913934663858 V
b. for ramp up process
EMF = -0.525*pi*r^2 = -0.07982786932771 V
c. in case 1, B is decreasing into the page, hence the induced B is increasing into the page hence induced EMF is clockwise
case 2, induced EMF is anticlockwise
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