Home I Student e Class M chapter 9 Begin Date: 7/23/2018 12:00:00 AM -DueDate: 8

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Home I Student e Class M chapter 9 Begin Date: 7/23/2018 12:00:00 AM -DueDate: 8/5/2018 11:00:00 AM End Date: 8 5/2018 11.00:00 AM (20% ) Problem 2: In the figure the center of gravity (CO) of the ple held by the ple vaulher is 2.05 m from the left hand, and the hands ane 0.69 m apart. The mass of the pole is 50 kg. Ctheexpertta.com D A 50% Part (a) Calculate the frce in newtons acted by hisngr hand Crade Semmay atanO acotano si 123 DegreesRadians 50% Part (b) Calculate the force in newtons cand by his lef Lal 6 8 3 5 0

Explanation / Answer

a)

d = distance between hands = 0.69 m

dL = distance of left hand from center of gravity = 2.05 m

dR = distance of right hand from center of gravity = d + dL = 0.69 + 2.05 = 2.74 m

w = weight of pole = mg = 5 x 9.8 = 49 N

using equilibrium of torque about the left hand

FR d = w  dL

FR (0.69) = (49) (2.05)

FR = 145.6 N

b)

using equilibrium of force in vertical direction

FL = FR + w

FL = 145.6 + 49

FL = 194.6 N

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