Consider a railroad bridge overa highway. A train passing over the bridgedislodg

ID: 1734869 • Letter: C

Question

Consider a railroad bridge overa highway.

A train passing over the bridgedislodges a

loose bolt from the bridge,which proceeds to

fall straight down and ends upbreaking the

windshield of a car passingunder the bridge.

The car was 26 m away from thepoint of

impact when the bolt began tofall down;

unfortunately, the driver didnot notice it and

proceeded at constant speed of28 m/s.

The acceleration of gravity is9.8m/s2 .

How high is the bridge? Or moreprecisely,

how high are the railroad tracksabove the

windshield height? Answer in units ofm

28*t=26 so t=26/28=0.9285sec height=1/2gt*t=1/2*9.8*0.9285*0.9285=4.224m

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