The electric field between two square metal plates is100 N/C. The plates are 1.3

Question

The electric field between two square metal plates is100 N/C. The plates are 1.3 m on a side and are separated by 5.0 cm. What is the charge on each plate (assumeequal and opposite)? Neglect edge effects. The electric field between two square metal plates is100 N/C. The plates are 1.3 m on a side and are separated by 5.0 cm. What is the charge on each plate (assumeequal and opposite)? Neglect edge effects. The field just outside a 3.20 cmradius metal ball is 2.40 x 10^2 N/C and points toward the ball. What charge resides on theball?

Explanation / Answer

Length (L) of each side of square plate = 1.3m Area (A) of square plate = L2                                      = (1.3m)2                                      = 2.69m2 Seperation (d) between the plates = 5.0cm                                                    = 0.05m We know the formula for the charge on each plate is                   Q = CV                       = (Ao / d)(Ed)                       = AEo .............. (1) Here o =8.85*10-12C2/N.m2          E = electricfield between the plates = 100 N/C By substituting all these values in the eq (1) we get thevalue of the charge (Q) on each square plate. Do the calculation work.          E = electricfield between the plates = 100 N/C By substituting all these values in the eq (1) we get thevalue of the charge (Q) on each square plate. Do the calculation work.

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.