A 15F Capacitor is connected to a 50-V battery andbecomes fully charged. The bat
ID: 1737209 • Letter: A
Question
A 15F Capacitor is connected to a 50-V battery andbecomes fully charged. The battery is removed and a slab ofdielectric that completely fills the space between the plates isinserted. If the dielectric has a constant of 5.0, a. What is the capacitance of the capacitor after the slab isinserted? b. What is the voltage across the capacitor's plates after theslab is inserted? A 15F Capacitor is connected to a 50-V battery andbecomes fully charged. The battery is removed and a slab ofdielectric that completely fills the space between the plates isinserted. If the dielectric has a constant of 5.0, a. What is the capacitance of the capacitor after the slab isinserted? b. What is the voltage across the capacitor's plates after theslab is inserted?Explanation / Answer
Given tha the capacitance of the given capacitor is C0 =15F = 15*10-6 F The voltage in the battery is V = 50 V The dielectric constant is K = 5.0 ------------------------------------------------------------------------ Let C is thecapacitance of the capacitor with dielectric constantthen C = KC0 =5.0* 15*10-6 F =75*10-6 F The charge onthe capacitor is q = C0*V =-------------- Columbs The voltage accross the capacitor is V = q /C = ------------ V =5.0* 15*10-6 F =75*10-6 F The charge onthe capacitor is q = C0*V =-------------- Columbs The voltage accross the capacitor is V = q /C = ------------ VRelated Questions
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