A parallel-plate capacitor with area 0.200 m2 (meter square)and plate separation

Question

A parallel-plate capacitor with area 0.200 m2 (meter square)and plate separation of 3.00 mm is connected to a 6.00-Vbattery. (a) what is the capacitance? (b) how much charge is stored onthe plates? (c) what is the ellctric field beween the plates? (d)find te magnitude of the charge density on each plate. (e) withoutdisconnecting the battery, the plates are moved farther apart.qualitatively, what happens to each of the previous answers? Thank you very mucch A parallel-plate capacitor with area 0.200 m2 (meter square)and plate separation of 3.00 mm is connected to a 6.00-Vbattery. (a) what is the capacitance? (b) how much charge is stored onthe plates? (c) what is the ellctric field beween the plates? (d)find te magnitude of the charge density on each plate. (e) withoutdisconnecting the battery, the plates are moved farther apart.qualitatively, what happens to each of the previous answers? Thank you very mucch

Explanation / Answer

Area A = 0.2 m 2 separation d = 3 mm = 3 * 10 -3 m Voltage V = 6 V (a). Capacitance C = A / d where = permitivity of free space = 8.85 * 10-12 C 2 / N m 2 (b). charge is stored on the plates is Q = C V (c).  the ellctric field beween the plates E = V /d (d). magnitude of the charge density on each plate = E (b). charge is stored on the plates is Q = C V (c).  the ellctric field beween the plates E = V /d (d). magnitude of the charge density on each plate = E

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