A block of mass 2.50 kg is pushed 2.20 m along a frictionless horizontal tableby

Question

A block of mass 2.50 kg is pushed 2.20 m along a frictionless horizontal tableby a constant 14.0 N forcedirected 25.0° below the horizontal. (a) Determine the work done by the applied force.
J

(b) Determine the work done by the normal force exerted by thetable.
J

(c) Determine the work done by the force of gravity.
J

(d) Determine the work done by the net force on the block.
J
(a) Determine the work done by the applied force.
J

(b) Determine the work done by the normal force exerted by thetable.
J

(c) Determine the work done by the force of gravity.
J

(d) Determine the work done by the net force on the block.
J

Explanation / Answer

Part a) W = Fdcos W = (14.0 N)(2.20 m)(cos25) W= 27.9 J b) 0 because the work done by the normal force is canceled out bythe work done by gravity. c) 0 because the work done by gravity is canceled out by the workdone by the normal force. d) Net force: totaled up everything; since b and c are zero, thenet force is the force done in A) 27.9 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.