At t = 0, a particle moving in the xy plane with constantacceleration has a velo

Question

At t = 0, a particle moving in the xy plane with constantacceleration has a velocity of Vi = (3.00i - 2.00j)m/s when it isat the origin. At t = 3.00s, the particle's velocity is v = (9.00i+ 7.00j)m/s. Find: a.) the acceleration of the particle b.) its coordinates at any time t. Please show all work for full points. At t = 0, a particle moving in the xy plane with constantacceleration has a velocity of Vi = (3.00i - 2.00j)m/s when it isat the origin. At t = 3.00s, the particle's velocity is v = (9.00i+ 7.00j)m/s. Find: a.) the acceleration of the particle b.) its coordinates at any time t. Please show all work for full points.

Explanation / Answer

   a.   Acceleration   a   =   (v   -   vi)/ t          vi   =   initialvelocity   =   3.00i   -   2.00j         m/s          v   =   velocityat time   t   =   9.00i    +   7.00j   m/s          t   =   time   =   3   s          a   =  { (9.00i   +   7.00j)   -   (3.00i   -   2.00 j)} /3   =   (2.00i   +   3.00j )           m/s2    b.   Position at anyinstant   t      x   =   x0   +   vi* t   +   (1/2) * a *t2       where x0 ispositionat   t   =   0       given   x0   =   0.00i   +   0.00j         (origin)          x   =   (0.00i   +   0.00j)   +   ( 3.00i    -   2.00 j) *t   +   (1/2) * ( 2.00i   +   3.00 j) * t2          x   =  {( 3.00+ t) * t } i   +   { (1.50t   -   2.00) * t}j               m          x   =  {( 3.00+ t) * t } i   +   { (1.50t   -   2.00) * t}j               m          

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