At t = 0, a particle moving in the xy plane with constantacceleration has a velo

Question

At t = 0, a particle moving in the xy plane with constantacceleration has a velocity of Vi = (3.00i - 2.00j)m/s when it isat the origin. At t = 3.00s, the particle's velocity is v = (9.00i+ 7.00j)m/s. Find: a.) the acceleration of the particle b.) its coordinates at any time t. Please show all work for full points. Will rate highly forgood answer At t = 0, a particle moving in the xy plane with constantacceleration has a velocity of Vi = (3.00i - 2.00j)m/s when it isat the origin. At t = 3.00s, the particle's velocity is v = (9.00i+ 7.00j)m/s. Find: a.) the acceleration of the particle b.) its coordinates at any time t. Please show all work for full points. Will rate highly forgood answer

Explanation / Answer

   a.   Acceleration   a   =   (Finalvelocity v   -  initialvelocity   u) / time t          a   =   {(9.00 i + 7.00 j)   -    (3.00 i- 2.00 j)} / (3.00 - 0)   =   (6.00i + 9.00 j) / 3.00          a   =   2.00i   +   3.00j            m/s2    b.   Position at any instantt is given by second equation of motion          s   =   u* t   +   (1/2) * a *t2          s   =   (3.00 i   -   2.00 j) *t   +   0.5 * (2.00i   +   3.00 j) * t2          s   =   { (3.00 + 1.00 * t) * t } i   -   {(2.00 - 1.50 * t) * t }j                        m          s   =   { (3.00 + 1.00 * t) * t } i   -   {(2.00 - 1.50 * t) * t }j                        m          

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