A proton moving with a velocity of 4 x 10^4 m/s enters amagnetic field of 0.20 T
ID: 1739351 • Letter: A
Question
A proton moving with a velocity of 4 x 10^4 m/s enters amagnetic field of 0.20 T. If the proton travels in thedirection of the magnetic field, what is the magnitude of themagnetic force on the proton? A) 1.1 x 10^-15 N B) 0 N C) 1.8 x 10^ -15 N D) 1.3 x 10^ -15 N E) 0.8 x 10^ -15 N Why?? A proton moving with a velocity of 4 x 10^4 m/s enters amagnetic field of 0.20 T. If the proton travels in thedirection of the magnetic field, what is the magnitude of themagnetic force on the proton? A) 1.1 x 10^-15 N B) 0 N C) 1.8 x 10^ -15 N D) 1.3 x 10^ -15 N E) 0.8 x 10^ -15 N Why??Explanation / Answer
B) 0 N Since proton travels parallel to the magneticfiield the magnetic field has no force on it. Force equal to zero.Related Questions
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