Hooke\'s law describes a certain light spring of unstretched length33.0 cm. When

Question

Hooke's law describes a certain light spring of unstretched length33.0 cm. When one end is attached to thetop of a door frame, and a 5.40-kg objectis hung from the other end, the length of the spring is45.00 cm. (a) Find its spring constant.
1 kN/m

(b) The load and the spring are taken down. Two people pull inopposite directions on the ends of the spring, each with a force of170 N. Find the length of the spring inthis situation.
2 m (a) Find its spring constant.
1 kN/m

(b) The load and the spring are taken down. Two people pull inopposite directions on the ends of the spring, each with a force of170 N. Find the length of the spring inthis situation.
2 m

Explanation / Answer

When 5.40 kg block is ahung , then force acting = mg =5.40*9.8= 52.92 N Also extension in the spring = 45 - 33 = 12 c m= 0.12 m So Spring constant = Force / extension = 52.92 /0.12 = 441 N/m =0.441 kN/m b) When 2 people pull in 2 direction , Then Tension in the spring = 170 N (Note that it will not be 340 N , because you have to considerthe tension ) Extension = Force / spring constant = 170 / 441 = 38.5cm So length = original length + extension = 71.5 cm

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