Are sin and cos switched here when calculating the i and jcompenents of vector 2

Question

Are sin and cos switched here when calculating the i and jcompenents of vector 2? I kept trying to figure out why it was this way, and then Isaw someone submitted it the other way, but then someone challengedthat, so I'm all confused. I thought if the vector was in the firstquadrant I would be using sin for the vertical component and cosfor the horizontal, but since I never took trig I just wanted tocheck. Thanks! Are sin and cos switched here when calculating the i and jcompenents of vector 2? I kept trying to figure out why it was this way, and then Isaw someone submitted it the other way, but then someone challengedthat, so I'm all confused. I thought if the vector was in the firstquadrant I would be using sin for the vertical component and cosfor the horizontal, but since I never took trig I just wanted tocheck. Thanks!

Explanation / Answer

If you measure the angle of the vector with respect to thehorizontal then the horizontal component is in terms of cos and vertical component is in terms of sin If you measure the angle of the vector with respect tothe vertical then the horizontal component is in termsof sin and vertical component is in terms of cos If you measure the angle of the vector with respect tothe vertical then the horizontal component is in termsof sin and vertical component is in terms of cos

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