How do you solve the problem in Knight\'s Physics forScientists and Engineers, 2

Question

How do you solve the problem in Knight's Physics forScientists and Engineers, 2nd e., #31.29: A 1.5 V battery provides .50 A of current. At what rate(C/s) is charge lifted by the charge escalator? How much workdoes the charge escalator do to lift 1.0 C of charge? What isthe power output of the charge escalator? How do you solve the problem in Knight's Physics forScientists and Engineers, 2nd e., #31.29: A 1.5 V battery provides .50 A of current. At what rate(C/s) is charge lifted by the charge escalator? How much workdoes the charge escalator do to lift 1.0 C of charge? What isthe power output of the charge escalator?

Explanation / Answer

If you think about it, this problem can be evaluated just bylooking at the units. So, C/s = A. The charge escalator must lift 0.5 C/s for the currentto be 0.5 A. For the second part: Volts is just J/C. Therefore, if there are 1.5V and 1 C of charge, the work is 1.5 V/ 1 C = 1.5 J/C The third part: Volt = W/A. Then, 12 V = Watts / 0.5 A. 12 V * 0.5 A = Watts =6 Watts

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