A tennis player swings her 920 g racket with a speed of9.5 m/s. She hits a 56 g

Question

A tennis player swings her 920 g racket with a speed of9.5 m/s. She hits a 56 g tennis ball that was approaching her at aspeed of 20.5 m/s. The ball rebounds at 42 m/s. How fast is herracket moving immediately after the impact? You can ignore theinteraction of the racket with her hand for the brief duration ofthe collision.

If the tennis ball and racket are in contactfor 9.66 ms, what is the average force that the racket exerts onthe ball? How does this compare to the gravitational force on theball?

Explanation / Answer

Applying the law of conervation of momentum we have as, m1u1+m2u2=m1v1+m2v2 0.92*9.5-0.056*20.5=0.92*v+0.056*42 v=5.6956m/s Hence we get by it. "Hope this helps!Best of luck for the rest of yourcoursework."

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