You and a friend are sitting in the outfield bleachers of a major league basseba
ID: 1742200 • Letter: Y
Question
You and a friend are sitting in the outfield bleachers of a major league basseball park, 140m from home plate on a day when the temperature is 20 degrees C. Your friend is listening to the radio commentary with headphones while watching. The broadcast network has a microphone located 17 m from home plate to pick up the sound as the bat hits the ball. This sound is transferred as an EM wave a distance of 75,000 km by satellite from the ball park to the radio. a) When the batter hits a hard line drive, who will hear the "crack" of the bat first, you or your friend, and what is the shortest time interval between the bat hitting the ball and one of you hearing the sound? b) How much later does the other person hear the sound?Explanation / Answer
. 1. c = speed of light and radio waves in air˜ 3.0E+8 meters/second 2. = speed of sound in air at20°C ˜ 330 meters/second 3. t1 = time for sound to travel17 meters = d1/ = (17 meters)/(330 meters/second)= 51.52E-3 seconds 4. t2 = time for sound to travel140 meters = d2/ = (140 meters)/(330meters/second) = 424.24E-3 seconds 5. t3 = time for radio waves totravel 75000 km = d3/c = (75000000)/(3.0E+8meters/second) = 250.0E-3 seconds 6. tfriend = t1 +t3 = 51.52E-3 seconds + 250.0E-3 seconds = 301.52E-3seconds 7. tyou = t2 =424.24E-3 seconds 8. Your friend will hear the "crack" of thebat first. 9. Theshortest time interval is 301.5 milliseconds. 10. You will hear the "crack" of the bat122.73 milliseconds after your friend hears the samesound. .Related Questions
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