An archer wants to determine the speed atwhich her new bow can fire an arrow. Sh

Question

An archer wants to determine the speed atwhich her new bow can fire an arrow. She paces off a distanced from her target and fires her arrow horizontally. Shedetermines that she launched it at a height h higher thanwhere it strikes the target. She ignores air resistance. Choose anexpression in terms of h, d and g thatshe can use to determine the initial speed of her arrow.
(a) dgh (b) dhg (c) d-gh An archer wants to determine the speed atwhich her new bow can fire an arrow. She paces off a distanced from her target and fires her arrow horizontally. Shedetermines that she launched it at a height h higher thanwhere it strikes the target. She ignores air resistance. Choose anexpression in terms of h, d and g thatshe can use to determine the initial speed of her arrow.
(a) dgh (b) dhg (c) d-gh (a) dgh (b) dhg (c) d-gh An archer wants to determine the speed atwhich her new bow can fire an arrow. She paces off a distanced from her target and fires her arrow horizontally. Shedetermines that she launched it at a height h higher thanwhere it strikes the target. She ignores air resistance. Choose anexpression in terms of h, d and g thatshe can use to determine the initial speed of her arrow.
(a) dgh (b) dhg (c) d-gh

Explanation / Answer

from dynamics basics we know: s = vt s = 1/2 at2 to figure out the horizontal speed, we fill in thehorizontal-coordinate in the first function and thevertical-coordinate in the second and rewrite: v = d/t t = 2h/g to calculate the speed, we substitute 't' in the firstfunction for the second, v = d/2h/g = d * 1 / 2h/g =dg/2h which is answer (a) to figure out the horizontal speed, we fill in thehorizontal-coordinate in the first function and thevertical-coordinate in the second and rewrite: v = d/t t = 2h/g to calculate the speed, we substitute 't' in the firstfunction for the second, v = d/2h/g = d * 1 / 2h/g =dg/2h which is answer (a)

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