An object 4.0 cm in height is placed 8.0 cmin front of a concave mirror with a f

Question

   An object 4.0 cm in height is placed 8.0 cmin front of a concave mirror with a focal length of 10.0 cm. What is the position of its image in relation to the mirror andwhat are its characteristics? A) 40.0 cm on the other side of the mirror, real, 6.0 timesbigger B) 10.0 cm on the other side of mirror, virtual, 10.0 timesbigger C) 40.0 cm on the other side of mirror, virtual, 5.0 timesbigger D) 10.0 cm on the same side of mirror, real, 6.0 timesbigger E) 18.0 cm on the same side of mirror, virtual, 2.25 timesbigger Why?    An object 4.0 cm in height is placed 8.0 cmin front of a concave mirror with a focal length of 10.0 cm. What is the position of its image in relation to the mirror andwhat are its characteristics? A) 40.0 cm on the other side of the mirror, real, 6.0 timesbigger B) 10.0 cm on the other side of mirror, virtual, 10.0 timesbigger C) 40.0 cm on the other side of mirror, virtual, 5.0 timesbigger D) 10.0 cm on the same side of mirror, real, 6.0 timesbigger E) 18.0 cm on the same side of mirror, virtual, 2.25 timesbigger Why?

Explanation / Answer

1/v+1/u=1/f 1/v+1/8=1/10 v=-40cm Magnification m=-v/u=-(-40)/8=5 40.0 cm on the other side of mirror, virtual, 5.0 timesbigger Hence we get by it.

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