3 The left pedestal is beingstretched. The right pedestal is beingstretched. The
ID: 1744325 • Letter: 3
Question
3 The left pedestal is beingstretched.The right pedestal is beingstretched.
The left pedestal is beingcompressed.
The right pedestal is beingcompressed.
3 The left pedestal is beingstretched.
The right pedestal is beingstretched.
The left pedestal is beingcompressed.
The right pedestal is beingcompressed.
3 Did you pick apivot point about which to calculate torques? Do you see that withan unknown force at each pedestal, that one of the ends should bethe pivot point? Did you write the torques about the pivot forthose two unknown forces and for the force on the board due to thediver's weight? Did you include the correct signs? After you findone of the unknown forces, did you write A balance-of-forcesequation for the vertical axis?
Explanation / Answer
Given : Weight (W) = 710 N Length (L ) = 4 m distance (d) = 1.5 m (a) The magnitude and direction of theforce on the board from the left pedestal is: f2 x d + f1 x 0 + W (- (L-d)) = 0 f2 = { W x (L-d) } / d = (- 720 * 2.5 ) / 1.5 = - 1200 Hence force is 1200 N actind downwards. (b) Themagnitude and direction of the force on the board from the rightpedestal is : f2 x 0 - ( - f1 ) d + W ( L ) = 0 f1 = ( W*L) / d = (720 * 4) / 1.5 = 1920 N upwards The left pedestal is beingstretched The right pedestal isbeing compressed.Hope this helps u!
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