Two cars collide at an intersection. Car A, with a mass of2000 kg, is going from

Question

Two cars collide at an intersection. Car A, with a mass of2000 kg, is going from west to east, while car B, of mass1300 kg, is going from north to south at 17.0 m/s. As aresult of this collision, the two cars become enmeshed and move asone afterwards. In your role as an expert witness, you inspect thescene and determine that, after the collision, the enmeshed carsmoved at an angle of 65.0 degree south of east from the pointof impact a)How fast were the enmeshed cars moving just after thecollision?                   v=          m/s b)How fast was car A going just before thecollision?                v=              m/s Two cars collide at an intersection. Car A, with a mass of2000 kg, is going from west to east, while car B, of mass1300 kg, is going from north to south at 17.0 m/s. As aresult of this collision, the two cars become enmeshed and move asone afterwards. In your role as an expert witness, you inspect thescene and determine that, after the collision, the enmeshed carsmoved at an angle of 65.0 degree south of east from the pointof impact a)How fast were the enmeshed cars moving just after thecollision?                   v=          m/s b)How fast was car A going just before thecollision?                v=              m/s

Explanation / Answer

Applying the law of conservation of momentum along x andy-axis is m1u1+m2u2=m1v1+m2v2 2000*u+1300*0=(2000+1300)*vcos65 2000*0+1300*-17=(2000+1300)*-vsin65 From this we get v the velocity of the enmeshed cars and bysubstituting this in any of the above we get the velocity of the car A collision as it. Hence we get by it.

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