A uniform ladder 5.0 m long rests against a frictionless,vertical wall with its

Question

A uniform ladder 5.0 m long rests against a frictionless,vertical wall with its lower end 3.0 m from the wall. The ladderweighs 155 N. The coefficient of staticfriction between the foot of the ladder and the ground is 0.40. Aman weighing 780 N climbs slowly up theladder. (c) How far along the ladder can the man climb before theladder starts to slip?
A uniform ladder 5.0 m long rests against a frictionless,vertical wall with its lower end 3.0 m from the wall. The ladderweighs 155 N. The coefficient of staticfriction between the foot of the ladder and the ground is 0.40. Aman weighing 780 N climbs slowly up theladder. (c) How far along the ladder can the man climb before theladder starts to slip?

Explanation / Answer

Here the net vertical force is 155N+780N = 935N Therefore maximum frictional force is 0.4*935N = 374N Now applying the torque equation about the point of contact ofthe ladder we get (4m)(374N) = (1.5m)(155N) + (x)(3/5)(780N) Then x = 2.7m (4m)(374N) = (1.5m)(155N) + (x)(3/5)(780N) Then x = 2.7m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.