An aluminum frying pan with a mass of 250 grams is heated on astove to 176 degre
ID: 1745633 • Letter: A
Question
An aluminum frying pan with a mass of 250 grams is heated on astove to 176 degrees Fahrenheit and then dropped into a sinkcontaining 750 grams of water at room temperature (20 degreesCelsius). Assuming that the tranfer of heat from one body to theother take place with no losses to the surrounding. a. What is the equilibrium temperature of the water andpen? b. How joules were lost by the frying pan? c. How many kilocalories were gained by the water? An aluminum frying pan with a mass of 250 grams is heated on astove to 176 degrees Fahrenheit and then dropped into a sinkcontaining 750 grams of water at room temperature (20 degreesCelsius). Assuming that the tranfer of heat from one body to theother take place with no losses to the surrounding. a. What is the equilibrium temperature of the water andpen? b. How joules were lost by the frying pan? c. How many kilocalories were gained by the water?Explanation / Answer
mass of pan M = 250 g initial temperature of pan t = 176 F = ( 5 / 9 ) ( 176 - 32 ) o C = 80 o C mass of water m = 750 g initial temperature of water t ' = 20 o C (a). heat lost by pan = heat gain by water M C dt = m c dt ' where C = specific heat of aluminium = 0.9 J/ g o C dt = 80 -T c= specific heat of water = 4.186 J / g o C dt ' = T-20 substitue values we get 250 * 0.9 * ( 80 - T ) = 750 *4.186 * ( T - 20 ) 72 - 0.9 T = 12.558 T - 251.16 T = 24 o C (b). heat lost by pan Q = M C ( 80 - 24 ) =250 * 0.9 * 56 = 12600 J (c). heat gain by water Q ' = m c ( 24 - 20 ) = 750 * 4.186 * 4 = 12558 J = 12558 / 4.186 cal = 3000 cal = 3 k calRelated Questions
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