The wave function for a traveling wave on a taut string is (inSI units) the foll
ID: 1745656 • Letter: T
Question
The wave function for a traveling wave on a taut string is (inSI units) the following equation. y(x, t) = (0.368 m)sin(8t - 1x +/4) (a) What are the speed and direction oftravel of the wave?m/s Directionpositive x-directionpositive y-directionpositive z-directionnegative x-directionnegative y-directionnegative z-direction
(b) What is the vertical position of an element of the string att = 0, x = 0.120m?
m
(c) What is the wavelength of the wave?
m
What is the frequency of the wave?
Hz
(d) What is the maximum magnitude of the transverse speed of thestring?
m/s y(x, t) = (0.368 m)sin(8t - 1x +/4) (a) What are the speed and direction oftravel of the wave?
m/s Directionpositive x-directionpositive y-directionpositive z-directionnegative x-directionnegative y-directionnegative z-direction
(b) What is the vertical position of an element of the string att = 0, x = 0.120m?
m
(c) What is the wavelength of the wave?
m
What is the frequency of the wave?
Hz
(d) What is the maximum magnitude of the transverse speed of thestring?
m/s
Explanation / Answer
Given y(x, t) = (0.368 m)sin(8t - 1x +/4) compare this with y = A sin ( t - k x + ) we get propagation constant k = angular frequency = 8 amplitude A = 0.368 m (a). speed v = / k = 8 m / s (b). the vertical position of an element of the string att = 0, x = 0.120 mis y = 0.368 m sin [ 8* 0 - *0.12 +/ 4] = -0.09524 m (c). wavelength = 2 / k = 2 m (d). frequency f = / 2 = 4 Hz (d). maximum magnitude of the transverse speed of the string =A =9.248 m / sRelated Questions
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