A wheel 1.70 m in diameter lies in avertical plane and rotates with a constant a

Question

A wheel 1.70 m in diameter lies in avertical plane and rotates with a constant angular acceleration of4.50 rad/s2. The wheel startsat rest at t = 0, and the radius vector of a certain pointP on the rim makes an angle of 57.3° with thehorizontal at this time. At t = 2.00 s find the following. (a) the angular speed of the wheel
1 rad/s

(b) the tangential speed and the total acceleration of the pointP
2 m/s
3 m/s2

(c) the angular position of the point P
4 rad (a) the angular speed of the wheel
1 rad/s

(b) the tangential speed and the total acceleration of the pointP
2 m/s
3 m/s2

(c) the angular position of the point P
4 rad

Explanation / Answer

a. f=i+t f=0+4.5*2 f=9rad/s b. v=r v=0.85*9m/s a=ar2+at2 ar=v2/r at=r c. f2-i2=2 =92/2*4.5 =9rad At t=2s we have as, =57.3*/180+9 Hence we get by it. At t=2s we have as, =57.3*/180+9 Hence we get by it.

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