temp near surface of earth 295 K an argon atom (atomic mass 39.948 u) has a kine

Question

temp near surface of earth 295 K an argon atom (atomic mass 39.948 u) has a kinetic energyequal to the average translational kinetic energy and is movingstraight up. If it does not collide with any other atoms ormolecules, how high up would it go before coming to rest? (Assume that the accel due to gravity is constant throughoutascent) thanks temp near surface of earth 295 K an argon atom (atomic mass 39.948 u) has a kinetic energyequal to the average translational kinetic energy and is movingstraight up. If it does not collide with any other atoms ormolecules, how high up would it go before coming to rest? (Assume that the accel due to gravity is constant throughoutascent) thanks

Explanation / Answer

Temperature near earth T = 295 K kinetic energy = ( 3/ 2 ) k T where k = Boltzmann constant = 1.38 * 10 ^ -23 J / K So, kinetic energy ( 1/ 2) m v ^ 2 = ( 3/ 2 ) ( 1.38 *10 ^ - 23 ) ( 295 )                                                    = 610.65 * 10 ^ -23 J from this velocity of the argon atom v = [ 2 *610.65 * 10 ^ -23 / m ] where m = mass of argon = 39.948 u = 39.948 * 1.67 * 10 ^ -27kg So, v = 1830.67 m / s maximum height go before coming to rest H = v ^ 2 /2g                                                                   = 170988 m

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