Work is done on the water by a rotating paddle wheel, which isdriven by two bloc

Question

Work is done on the water by a rotating paddle wheel, which isdriven by two blocks falling at a constant speed. The temperatureof the stirred water increases due to friction between the waterand the paddles. If the energy lost in the bearings and through thewalls is neglected, then the loss in potential energy associatedwith the blocks equals the work done by the paddle wheel on thewater. If each block has a mass of 1.50 kg and the insulated tankis filled with 200 g of water, what is the increase in temperatureof the water after the blocks fall through a distance of 2.75m?

Explanation / Answer

Energy lost by each block = m g h = 1.50 * 9.8 * 2.75 =   40.425 Joules , Energy lost by both blocks =   2 *40.425   = 80.85 Joules . This goes to heat the water...    Q = m cT .           80.85 = 200 * 4.186 * T . T =    0.0966 deg C   is the increase intemp

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