An object is held 10 cm away from a lens.The lens has a focal length of -6.8cm.
ID: 1747961 • Letter: A
Question
An object is held 10 cm away from a lens.The lens has a focal length of -6.8cm.a.) Determine the image distance.
1 cm
b.) Determine the magnification.
2
c.) If the object is 9.8 cm long,determine the image height.
3 cm
d.) Which of the followingare true about the image? Choose all that apply. 4 The image is virtual.
The image is inverted.
The image is upright.
The image is real.
e.) Which of the followingare true about the lens? Choose all that apply. 5 The lens is convex.
The lens is concave.
The lens is diverging.
The lens isconverging.
4 The image is virtual.
The image is inverted.
The image is upright.
The image is real.
4 The image is virtual.
The image is inverted.
The image is upright.
The image is real.
4 5 The lens is convex.
The lens is concave.
The lens is diverging.
The lens isconverging.
5 The lens is convex.
The lens is concave.
The lens is diverging.
The lens isconverging.
5
Explanation / Answer
focallength f = 46.9cm objectdistance u = -0.3 cm ( -ve sign due to sign convention) imagedistance = v a. 1/f = 1/v - 1/u 1/46.9 = 1/v - 1/(-0.3) v = 46.9* 0.3 / (0.3 - 46.9) = - 0.302 cm (-ve sign indicates that the image is formed on same side i.e. tothe left of lens) b. Magnification m = - v/ u = -(-0.302) / ( -0.30) = -1.007 c. m = hi/ ho heightofimage hi = 1.007* 1.8 = 1.813 cm heightofimage hi = 1.007* 1.8 = 1.813 cm d. The image is upright Theimage is virtual e. Lens in convex Lens isconverging.Related Questions
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