Two 5.0-cm-diameter metal disks are separated by a0.20-mm-thick piece of paper.

Question

Two 5.0-cm-diameter metal disks are separated by a0.20-mm-thick piece of paper. a.) What is the capacitance? b.) What is the maximum potential difference between thedisks? Here's helpful information that I feel is needed: Dielectric constant for paper = 3.7 Dielectric strength Emax (106 V/m) =16 I'm getting an answer of 3.21 x 10-10 F for a.) andI didn't even attempt b.) based on how many times I've done thisproblem and still not gotten a.) right. The answer in the back of the book is a.) 1.29F and b.) 3.2kV. Thanks. Two 5.0-cm-diameter metal disks are separated by a0.20-mm-thick piece of paper. a.) What is the capacitance? b.) What is the maximum potential difference between thedisks? Here's helpful information that I feel is needed: Dielectric constant for paper = 3.7 Dielectric strength Emax (106 V/m) =16 I'm getting an answer of 3.21 x 10-10 F for a.) andI didn't even attempt b.) based on how many times I've done thisproblem and still not gotten a.) right. The answer in the back of the book is a.) 1.29F and b.) 3.2kV. Thanks.

Explanation / Answer

given . diameter of disk (d)= 5.0cm = 0.05m distance separated = d = 0.20 mm = 0.20*10-3m dielectric const = k = 3.7 Emax = 16 (a) capacitence = c = k0 A/d-----(1) here we are considering m disks means circular shape soare of disk is = (d/2)2 = A and 0 = 8.85*1012c2/NM2 plug values in eq (1) you will get answer. (b) maxiumum potential difference = vmax =EMax d = 16*106 *(0.20)*10-3 = 3.2*103 v = 3.2 kv

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