Two 5.0cm x 5.0cm metal electrodes are spaced 1.2mm apart and connected by wires

Question

Two 5.0cm x 5.0cm metal electrodes are spaced 1.2mm apart and connected by wires to the terminals of a 9.0 V battery.

Part A:
What is the charge on each electrode? answer should be in pC
Express your answer using two significant figures.

Part B: What is the potential difference between electrodes? answer should be in V
Express your answer using two significant figures.

Part C: The wires are disconnected, and insulated handles are used to pull the plates apart to a new spacing of 2.4 .
What is the charge on each electrode? answer should be in pC
Express your answer using two significant figures.

Part D:What is the potential difference between electrodes? answer should be in V
Express your answer using two significant figures.

Please any physics expert and solve this problem, I havent been sleeping at nights trying to figure this one out, thanks so much.

Explanation / Answer

You should have a formula somewhere in your book that relates area and distance to capacitance. If they are reasonably shaped, it is C = A0/d.

Once you have C, q = CV so multiply C by the voltage to get q. That's part A.

Part B is of course 9.0 volts.

For the last two parts, recalculate C at the new distance and since the wires have been disconnected V is no longer 9 volts; but q stays the same as the first part (there's part C) because it has nowhere to go. So recalculate the new V using the new C and the old q, and that's part D.

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