Two parallel plates each of area A are spaced adistance d and connected by wires

Question

Two parallel plates each of area A are spaced adistance d and connected by wires to the terminals of abattery voltage . (a) Find an expression for the charge on the positive plate,the electric field strength, and the potential difference betweenthe two plates in magnitude. (b) The wires are disconnected and insulated handles are usedto pull the plates apart to a new spacing of 4d. Now find thecharge on the positive plate, the electric field strength, and thepotential difference between them in magnitude. Two parallel plates each of area A are spaced adistance d and connected by wires to the terminals of abattery voltage . (a) Find an expression for the charge on the positive plate,the electric field strength, and the potential difference betweenthe two plates in magnitude. (b) The wires are disconnected and insulated handles are usedto pull the plates apart to a new spacing of 4d. Now find thecharge on the positive plate, the electric field strength, and thepotential difference between them in magnitude.

Explanation / Answer

Two parallel plates each of area A are spaced adistance d and connected by wires to the terminals of abattery voltage . Then the capacitance (C) of the capacitor is                C = Ao / d Now formula for the charge on the positive plate of thecapacitor is             Q = C                 = (Ao / d) Electric field strength is E = / d Potential field difference between the two plates is = Ed

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.