Heading straight toward the summit of Pikes Peak, an airplane ofmass 12000 kg fl

Question

Heading straight toward the summit of Pikes Peak, an airplane ofmass 12000 kg flies over the plains of Kansas at nearly constantaltitude 4.30 km with constant velocity 175 m/s west.
a) What is the airplane's vector angular momentum relative toa wheat farmer on the ground directly below the airplane?
b) Does this value change as the airplane continues its motionalong a straight line?
c) What is its angular momentum relative to the summit ofPikes Peak?
a) What is the airplane's vector angular momentum relative toa wheat farmer on the ground directly below the airplane?
b) Does this value change as the airplane continues its motionalong a straight line?
c) What is its angular momentum relative to the summit ofPikes Peak?

Explanation / Answer

a)the airplane's vector angular momentum relative to a wheatfarmer on the ground directly below the airplane L = m * v * S m = 12000 kg,v = 175 m/s and S = 4.30 km = 4.30 * 10^3 m b)the angular momentum of the airplane when it continues itsmotion along a staright line does not change.This is because thealtitude of the airplane does not change. c)the angular momentum relative to the summit of PikesPeak L1 = m * v * S1 tan = (S1/S) or S1 = S * tan or L1 = m * v * S * tan here = 0o or L1 = m * v * S * tan(0o) = 0 therefore there is no change in angular momentum. or L1 = m * v * S * tan(0o) = 0 therefore there is no change in angular momentum.

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