Q.An inter-city train in getmany has a scheduled average pseedof 216km/h. If the

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Q.An inter-city train in getmany has a scheduled average pseedof 216km/h. If the train goes around a curve at that speed and themagnitude of the acceleration experienced by the passenger is tobelimited to 5% of the gravitational acceleration, what is thesmallest radius of curvature for the track that can betolerated?
A. 7.3km Q. In the figure shown below, a 3.5kg block is acceleratedfrom rest by a compressed spring of spring constant 640 N/m . Theblock leaves the spring at the spring's relaxed length and thentravels over a horizontal floor with a coefficient of kineticfriction uk= 0.25. The frictional force stops the block in distanceD= 7.80 m . What is the increase in the thermal energy of the block- floor system due frinction? A.67J Please show works out.
Thanks. P.s Can anyone give me a all the work out sheet for final_A07for uts physical modelling 1? ill send you Q file.
Thank you Q.An inter-city train in getmany has a scheduled average pseedof 216km/h. If the train goes around a curve at that speed and themagnitude of the acceleration experienced by the passenger is tobelimited to 5% of the gravitational acceleration, what is thesmallest radius of curvature for the track that can betolerated?
A. 7.3km Q. In the figure shown below, a 3.5kg block is acceleratedfrom rest by a compressed spring of spring constant 640 N/m . Theblock leaves the spring at the spring's relaxed length and thentravels over a horizontal floor with a coefficient of kineticfriction uk= 0.25. The frictional force stops the block in distanceD= 7.80 m . What is the increase in the thermal energy of the block- floor system due frinction? A.67J Please show works out.
Thanks. P.s Can anyone give me a all the work out sheet for final_A07for uts physical modelling 1? ill send you Q file.
Thank you

Explanation / Answer

let speed of the train be = v if the acceleration that must be experience by thepassenger is = 0.05*9.8m/sec^2 = a then a = v^2 / r    and r = v^2 / a plugging in the values of v and a in the above equationwe can solve for miniumum radisu of curvature ' r ' . b) let the spring compression = x then the kinetic energy that is transferred to theBlock            E = k * x = mg * d plugging in the values of m(mass), (friction coff), g(gravity) and d we can solve for E after travelling a distance d the total kineticenergy of the mass if disspated aganist the friction with the floor , hence the thermal energy increase between the surface ofthe block and floor is the kientic energy of the block = E

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