A stone is thrown straight up from the ground with an initialspeed of 35.4 m/s.

Question

A stone is thrown straight up from the ground with an initialspeed of 35.4 m/s. At the same instant, a stone is droppedfrom a height of h meters above the ground level. The twostones strike the ground simultaneously. The acceleration of gravity is 9.8 m/s2 . Find theheight h. A stone is thrown straight up from the ground with an initialspeed of 35.4 m/s. At the same instant, a stone is droppedfrom a height of h meters above the ground level. The twostones strike the ground simultaneously. The acceleration of gravity is 9.8 m/s2 . Find theheight h.

Explanation / Answer

vertical displacement of the first stone=0 g=acceleration due to gravity=9.8 let the first stone took t s to hit the ground initial velocity=u=35.4 m/s s=u*t-(1/2)*g*t2 0=35.4*t-(1/2)*9.8*t2 (since t not equal to 0) t=7.22 s the second stone took 7.22 s to hit the ground initial velocity of the second stone=0 h=u*t+(1/2)*g*t2 h=0+(1/2)*g*7.222 h=255.75 m (ans)

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.