A 150-turn solenoid carries a current of 12 A. The radius ofthe solenoid is 0.05

Question

A 150-turn solenoid carries a current of 12 A. The radius ofthe solenoid is 0.050 m; and its length is 0.18 m. Determine themagnetic flux through the circular cross-sectional area at thecenter of the solenoid.

b. 4.3 ×10–4 Wb
c. 9.9 ×10–5 Wb
d. 7.0 ×10–4 Wb
e. 2.2 × 10–3 Wb A 150-turn solenoid carries a current of 12 A. The radius ofthe solenoid is 0.050 m; and its length is 0.18 m. Determine themagnetic flux through the circular cross-sectional area at thecenter of the solenoid. 4.3 ×10–4 Wb 9.9 ×10–5 Wb 7.0 ×10–4 Wb 2.2 × 10–3 Wb

Explanation / Answer

the magnetic field is B = nI
where n is no of turns per unit length
so n = 150/0.18
now magnetic flux = B.A
                           = nI*A
                             = 4*10-7 *(150/0.18)*(12*2**0.05*0.18)

cross section area is 2rh for cylinder
                            = 7.09 X 10-4 Wb

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