A cannon sends a projectile towards a target a distance 1350 maway. The initial

Question

A cannon sends a projectile towards a target a distance 1350 maway. The initial velocity makes an angle of 23 degrees withthe horizontal. The target is hit. The aceleration of gravity is 9.8 meters per second. What is the magnitude of the initial velocity? A cannon sends a projectile towards a target a distance 1350 maway. The initial velocity makes an angle of 23 degrees withthe horizontal. The target is hit. The aceleration of gravity is 9.8 meters per second. What is the magnitude of the initial velocity?

Explanation / Answer

The distance between the target and point of projectionis R = 1350 m The angle of projection is = 230 -----------------------------------------------------------------------------    The range of projectile is R =U2 sin2 /g                                 1350m = U2sin460 /g                                    1350m =U2 sin460 /9.8m/s2                                                U = ( 1350m * 9.8m/s2 / sin460)1/2                                             =---------- m/s                  This is the magnitude of the initial velocity -----------------------------------------------------------------------------    The range of projectile is R =U2 sin2 /g                                 1350m = U2sin460 /g                                    1350m =U2 sin460 /9.8m/s2                                                U = ( 1350m * 9.8m/s2 / sin460)1/2                                             =---------- m/s                                                      =---------- m/s                  This is the magnitude of the initial velocity

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