Hello! Would really appreciate any help here. :) A body of mass m1, initially tr

Question

Hello! Would really appreciate any help here. :) A body of mass m1, initially travelling with velocity v, makesa perfectly elastic head-on collision with a second body of massm2, initially at rest. After collision, m1 moves with velocity v1and m2 moves with velocity v2. Conservation of total linear momentum of the two bodies: m1 v = m1 v1 + m2 v2 Relative speed of approach equals relative speed of separationof the two bodies: v = v2 - v1 Fraction of the initial kinetic energywhich is transferred to the second body: 4 m1m2 / (m1 + m2)^2 Question 1. State the value of m2 / m1 for which the abovefraction has a maximum value. Briefly describe the motion of thetwo bodies at this maximum value. 2. And, given that the body of mass m1 travels at aninitial velocity of v of 6.0 ms^-1, find the velocity of thetwo bodies after collision, given that the mass m1 is twice themass m2. Hello! Would really appreciate any help here. :) A body of mass m1, initially travelling with velocity v, makesa perfectly elastic head-on collision with a second body of massm2, initially at rest. After collision, m1 moves with velocity v1and m2 moves with velocity v2. Conservation of total linear momentum of the two bodies: m1 v = m1 v1 + m2 v2 Relative speed of approach equals relative speed of separationof the two bodies: v = v2 - v1 Fraction of the initial kinetic energywhich is transferred to the second body: 4 m1m2 / (m1 + m2)^2 Question 1. State the value of m2 / m1 for which the abovefraction has a maximum value. Briefly describe the motion of thetwo bodies at this maximum value. 2. And, given that the body of mass m1 travels at aninitial velocity of v of 6.0 ms^-1, find the velocity of thetwo bodies after collision, given that the mass m1 is twice themass m2.

Explanation / Answer

(2) intial velocity of = u1= 6.0m/s mass of m1 = 2m2            m2= m2 final velocity of fist body after collision v1 =(m1-m2)/m1+m2 *u1     second body= v2=2m1/m1+m2 *u1 plug values and solve it. plug values and solve it.

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