Three conducting spheres of radii a, b and c, respectively,are connected by negl

Question

Three conducting spheres of radii a, b and c, respectively,are connected by negligibly thin conducting wires. Distancesbetween spheres are much larger than their sizes. The electricfield on the surface of the sphere of radius a is measured to beequal to Ea. What is the total charge Q that this system of threespheres holds? How much work do we have to do to bring a very smallcharge q from infinity to the sphere of radius b? NOTE: Please, this question is due at midnight tonight and Iwould appreciate anyone to respond to this problem for I have noclue at all. Agaain, thank you members and looking forward for thecorrect answers. Three conducting spheres of radii a, b and c, respectively,are connected by negligibly thin conducting wires. Distancesbetween spheres are much larger than their sizes. The electricfield on the surface of the sphere of radius a is measured to beequal to Ea. What is the total charge Q that this system of threespheres holds? How much work do we have to do to bring a very smallcharge q from infinity to the sphere of radius b? NOTE: Please, this question is due at midnight tonight and Iwould appreciate anyone to respond to this problem for I have noclue at all. Agaain, thank you members and looking forward for thecorrect answers.

Explanation / Answer

given the electric field on the spher a         Ea =Qa/ Aa Q= charge on the surface of the sphere Aa = surface area of the spher ' a ' e = permitivity of free space       if total charge on the three spheres is Q          Q /A = Qa +Qb +Qc /Aa+Ab+Ac                       and              Q /A = Qa / Aa   =Qb /Ab = Qc / Ac             Qa / r2a   =Qb /r2b = Qc /r2c   Aa  ,Ab ,Ac & Qa Qb Qc   and areas and charges on thesurfaces of teh sphere a ,b and c respectively.                             from above relation we can solve for total charge Q, b) the potential energy on the surface of the sphere will bethe work done to take the a test charge from the surface to spher 'b ' alone to inifinet distence           W=  V = Qb / 4rb             Qa / r2a   =Qb /r2b = Qc /r2c   Aa  ,Ab ,Ac & Qa Qb Qc   and areas and charges on thesurfaces of teh sphere a ,b and c respectively.                             from above relation we can solve for total charge Q, b) the potential energy on the surface of the sphere will bethe work done to take the a test charge from the surface to spher 'b ' alone to inifinet distence           W=  V = Qb / 4rb              from the value of Qb we can solve for work done .                                    

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