An airplane is flying horizontally at a speed of 380m/s, whenan engine falls off

Question

An airplane is flying horizontally at a speed of 380m/s, whenan engine falls off. Neglecting air resistance, if it takes30s for the engine to reach the ground, how high is the airplaneand how far does the engine travel horizontally while itfalls? 4410 m, 8820m or 8400m I'm not sure if this a textbook question...what equation am Inot seeing? If the plane continues to fly at the same velocity, where isthe engine relative to the airplane, when the engine reaches theground? ahead, behind, or just below it An airplane is flying horizontally at a speed of 380m/s, whenan engine falls off. Neglecting air resistance, if it takes30s for the engine to reach the ground, how high is the airplaneand how far does the engine travel horizontally while itfalls? 4410 m, 8820m or 8400m I'm not sure if this a textbook question...what equation am Inot seeing? If the plane continues to fly at the same velocity, where isthe engine relative to the airplane, when the engine reaches theground? ahead, behind, or just below it

Explanation / Answer

Initial Vertical Velocity = 0 m/s d = ut+(1/2)a(t^2) d=(0)(30)+(1/2)(9.81)(30^2) d=4414.5 which is approx. 4410 When the engine drops from the plane, they have the same horizontalvelocity. Since we are neglecting air resistance and gravity onlyacts in the y direction we can say that both the engine and planmaintain the same horizontal velocity while the engine falls for 30seconds, so when the engine hits the ground, it is directly belowthe plane.

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