A .2Kg block trveling right @ 6m/s runs head on into a block .4Kg traveling left

Question

A .2Kg block trveling right @ 6m/s runs head on into a block .4Kg traveling left @ 2m/s. The two blocks stick together and move as one after collision. I found the speed of the blocks after collision as 3.33m/s. Now I need to find what direction they will move after collision and What impulse did the .2Kg block receive from the .4Kg block. I did the momentum formulas for the direction and got 1.2 for block going right and .8 for block going left so I assume that they both will go right. But I am not sure if this was what I was supposed to do. I am completely lost on finding impulse. The only formula I find for impulse has time in it and I don't have a time given. Can anyone tell me what formulas I need to use to get these?

Explanation / Answer

Choose right as positive direction. for 0.2 kg, initial velocity v = 6 m/s, final velocity u = 3.33m/s, change in momentum = m(u - v) = -0.534 kgm/s, which is equalto the impulse received from the 0.4 kg block, or -0.534 N-s

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