A -10.9nC point charge and a +17.3nC point charge are 14.9cm apart on the x-axis

Question

A -10.9nC point charge and a +17.3nC point charge are 14.9cm apart on the x-axis. What is the electric potential at the point on the x-axis where the electric field is zero? 4.44x101v You are correct Your receipt no. is 163-3401Previous Tries What is the magnitude of the electric field at the two points on the x-axis where the electric potential is zero? (Input your answers in order of increasing distance from the negative point charge.) 4.81x104 N/C You are correct Your receipt no. is 163-4220Previous Tries Submit Answer Incorrect. Tries 5/10 Previous Tries

Explanation / Answer

b] Let first charge be at origin, then potential will be zero at x= 14.9*10.9/(10.9+17.3) cm = 5.76 cm

E = summation kq/r^2 = 9e9*10.9e-9/0.0576^2 + 9e9*17.3e-9/(0.149-0.0576)^2 = 48206 N/C

another location will be at x (in negative x axis) such that, -10.9/-x + 17.3/(0.149-x) = 0

x = 0.254 m

Electric field E = summation kq/r^2 = 9e9*10.9e-9/0.254^2 - 9e9*17.3e-9/(0.149+0.254)^2

= 562 N/C answer

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