1. The gravitational force of attraction between two studentssitting at their de
ID: 1753775 • Letter: 1
Question
1. The gravitational force of attraction between two studentssitting at their desks in physics class is 3.32 x 10^-8 N. (a.) If one student has a mass of 44.3 kg and the other has amass of 68.5 kg, how far apart are the students sitting? Theuniversal gravitational constant is 6.673 x 10^-11 N m^2/kg^2.Answer in units of m.2. A black hole is an object so heavy that neither matter noreven light can escape the influence of its gravitational field.Since no light can escape from it, it appears black. Suppose a massapproximately the size of the Earth's mass 6.72 x 10^24 kg ispacked into a small uniform sphere of radiusr. USE: The speed of light c= 2.99792x 10^8 m/s. The universal gravitational constantG= 6.67259 x 10^-11 Nm^2/kg^2. HINT: The escape speed must be the speed oflight. Based on Newtonian mechanics, determine the limiting radiusr0 when this mass (approximately the size of the Earth'smass) becomes a black hole. Answer in units of m. (a.) If one student has a mass of 44.3 kg and the other has amass of 68.5 kg, how far apart are the students sitting? Theuniversal gravitational constant is 6.673 x 10^-11 N m^2/kg^2.Answer in units of m.
2. A black hole is an object so heavy that neither matter noreven light can escape the influence of its gravitational field.Since no light can escape from it, it appears black. Suppose a massapproximately the size of the Earth's mass 6.72 x 10^24 kg ispacked into a small uniform sphere of radiusr. USE: The speed of light c= 2.99792x 10^8 m/s. The universal gravitational constantG= 6.67259 x 10^-11 Nm^2/kg^2. HINT: The escape speed must be the speed oflight. Based on Newtonian mechanics, determine the limiting radiusr0 when this mass (approximately the size of the Earth'smass) becomes a black hole. Answer in units of m.
Explanation / Answer
(a.) If one student has a mass of 44.3 kg and the other has amass of 68.5 kg, how far apart are the students sitting? Theuniversal gravitational constant is 6.673 x 10^-11 N m^2/kg^2.Answer in units of m.F=Gm1m2/R2
R =distance between thestudents=Gm1m2/F=2.4696m
2. A black hole is an object so heavy that neither matter noreven light can escape the influence of its gravitational field.Since no light can escape from it, it appears black. Suppose a massapproximately the size of the Earth's mass 6.72 x 10^24 kg ispacked into a small uniform sphere of radius r. Based on Newtonian mechanics, determine the limiting radiusr0 when this mass (approximately the size of the Earth'smass) becomes a black hole. Answer in units of m.
USE: The speed of light c= 2.99792x 10^8 m/s. The universal gravitational constantG= 6.67259 x 10^-11 Nm^2/kg^2. HINT: The escape speed must be the speed of light.
escape speed=v=2*GM/r0
v2=2*GM/r0
now limiting radius=r0=2*GM/v*v=2*6.67259*10-11*6.72 x10^24 /(2.99792 x 10^8)2
=9.9782*10-3m
USE: The speed of light c= 2.99792x 10^8 m/s. The universal gravitational constantG= 6.67259 x 10^-11 Nm^2/kg^2. HINT: The escape speed must be the speed of light.
escape speed=v=2*GM/r0
v2=2*GM/r0
now limiting radius=r0=2*GM/v*v=2*6.67259*10-11*6.72 x10^24 /(2.99792 x 10^8)2
=9.9782*10-3m
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